document.write( "Question 1092629: How many quarts of pure antifreeze must be added to 5 quarts of a 10% antifreeze solution to obtain a 20% antifreeze solution? \n" ); document.write( "

Algebra.Com's Answer #707256 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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How many quarts of pure antifreeze must be added to 5 quarts of a 10% antifreeze solution to obtain a 20% antifreeze solution?
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\n" ); document.write( "let x = amt of pure antifreeze required
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\n" ); document.write( "The equation using decimal equiv of percent
\n" ); document.write( ".10(5) + x = .20(x+5)
\n" ); document.write( ".50 + x = .20x + 1
\n" ); document.write( "x - .20x = 1 - .5
\n" ); document.write( ".8x = .5
\n" ); document.write( "x - .5/.8
\n" ); document.write( "x = .625 qts of pure antifreeze required
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