document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1092566>Question 1092566</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Professor Johnson gives only midterm exam and a final exam. The semester average is<BR>\n" );
document.write( "computed by taking 1/3 of the midterm exam score plus 2/3 of the final exam score. To get a C, Beth must have a<BR>\n" );
document.write( "semester average between 70 and 79 inclusive. If Beth scored only 64 on the midterm, then for what range of scores<BR>\n" );
document.write( "on the final exam would Beth earn a C? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #707209 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=707209\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let M represent the mideterm score.<BR>\n" );
document.write( "let F represent the final score.<BR>\n" );
document.write( "let A represent the overall score.\r<BR>\n" );
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document.write( "the formula is A = 1/3 * M + 2/3 * F\r<BR>\n" );
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document.write( "when M = 64, this formula becomes A = 1/3 * 64 + 2/3 * F\r<BR>\n" );
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document.write( "simplify to get A = 64/3 + 2/3 * F\r<BR>\n" );
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document.write( "when A = 70, this formula becomes 70 = 1/3 * 64 + 2/3 * F\r<BR>\n" );
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document.write( "multiply both sides of this equation by 3 to get 210 = 64 + 2 * F\r<BR>\n" );
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document.write( "solve for F to get F = (210 - 64) / 2 = 73\r<BR>\n" );
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document.write( "she needs to get a 73 on the final in order for the overall score to be equal to 70.\r<BR>\n" );
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document.write( "1/3 * 64 + 2/3 * 73 = 70\r<BR>\n" );
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document.write( "when A = 79, this formula becomes 79 = 1/3 * 64 + 2/3 * F\r<BR>\n" );
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document.write( "multiply both sides of the equation by 3 to get 237 = 64 + 2 * F\r<BR>\n" );
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document.write( "solve for F to get F = (237 - 64) / 2 = 86.5\r<BR>\n" );
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document.write( "she needs to get an 86.5 on the final in order for the overall score to be equal to 79.\r<BR>\n" );
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document.write( "1/3 * 64 + 2/3 * 86.5 = 79\r<BR>\n" );
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document.write( "in order to get a C, which is any score from 70 to 79, she needs to get any score from 73 to 86.5 on the final.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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