document.write( "Question 1092560: bob leaves home in Chicago at 9a.m. and travels east at a steady 60 mph.
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document.write( "Susan, 400 miles to the east in Pittsburgh leaves at the same time and travels west at a steady 40 mph. where will they meet? \n" );
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Algebra.Com's Answer #707173 by josmiceli(19441) You can put this solution on YOUR website! Their speeds will add since they \n" ); document.write( "are going in opposite directions \n" ); document.write( "------------------------------- \n" ); document.write( "You can think of this as Susan standing \n" ); document.write( "still and Bob traveling at the sum of their speeds \n" ); document.write( "Let \n" ); document.write( "--------------------------------------------- \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "----------------------- \n" ); document.write( "In 4 hrs, Bob travels \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "---------------------- \n" ); document.write( "In 4 hrs, Susan travels \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "----------------------- \n" ); document.write( "check: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "----------------------------- \n" ); document.write( "They will meet 240 mi from Chicago \n" ); document.write( "and 160 mi from Pittsburgh\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |