document.write( "Question 1092560: bob leaves home in Chicago at 9a.m. and travels east at a steady 60 mph.
\n" ); document.write( "Susan, 400 miles to the east in Pittsburgh leaves at the same time and travels west at a steady 40 mph. where will they meet?
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Algebra.Com's Answer #707173 by josmiceli(19441)\"\" \"About 
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Their speeds will add since they
\n" ); document.write( "are going in opposite directions
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\n" ); document.write( "You can think of this as Susan standing
\n" ); document.write( "still and Bob traveling at the sum of their speeds
\n" ); document.write( "Let \"+t+\" = time in hrs for them to meet
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\n" ); document.write( "\"+400+=+%28+60+%2B+40+%29%2At+\"
\n" ); document.write( "\"+100t+=+400+\"
\n" ); document.write( "\"+t+=+4+\" hrs
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\n" ); document.write( "In 4 hrs, Bob travels
\n" ); document.write( "\"+d%5B1%5D+=+60%2A4+\"
\n" ); document.write( "\"+d%5B1%5D+=+240+\"
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\n" ); document.write( "In 4 hrs, Susan travels
\n" ); document.write( "\"+d%5B2%5D+=+40%2A4+\"
\n" ); document.write( "\"+d%5B2%5D+=+160+\"
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\n" ); document.write( "check:
\n" ); document.write( "\"+d%5B1%5D+%2B+d%5B2%5D+=+240+%2B+160+\"
\n" ); document.write( "\"+d%5B1%5D+%2B+d%5B2%5D+=+400+\" mi
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\n" ); document.write( "They will meet 240 mi from Chicago
\n" ); document.write( "and 160 mi from Pittsburgh\r
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