document.write( "Question 97143: Desa invested a certain amount of money at 4% interest and $1500 more than that amount at 7%. Her total yearly interest was $435. How much did she invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #70717 by checkley71(8403)\"\" \"About 
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.04X+.07(X+1500)=435
\n" ); document.write( ".04X+.07X+105=435
\n" ); document.write( ".11X=435-105
\n" ); document.write( ".11X=330
\n" ); document.write( "X=330/.11
\n" ); document.write( "X=3000 AMOUNT INVESTED @ 4%
\n" ); document.write( "3000+1500=4500 INVESTED @ 7%
\n" ); document.write( "PROOF
\n" ); document.write( ".04*3000+.07*4500=435
\n" ); document.write( "120+315=435
\n" ); document.write( "435=435
\n" ); document.write( "
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