document.write( "Question 97143: Desa invested a certain amount of money at 4% interest and $1500 more than that amount at 7%. Her total yearly interest was $435. How much did she invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #70717 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! .04X+.07(X+1500)=435 \n" ); document.write( ".04X+.07X+105=435 \n" ); document.write( ".11X=435-105 \n" ); document.write( ".11X=330 \n" ); document.write( "X=330/.11 \n" ); document.write( "X=3000 AMOUNT INVESTED @ 4% \n" ); document.write( "3000+1500=4500 INVESTED @ 7% \n" ); document.write( "PROOF \n" ); document.write( ".04*3000+.07*4500=435 \n" ); document.write( "120+315=435 \n" ); document.write( "435=435 \n" ); document.write( " |