document.write( "Question 1092541: Solve show work y+1/y+6 + 5y/y^2-36=y-3/y-6 \n" ); document.write( "

Algebra.Com's Answer #707165 by Boreal(15235) $\"\"$ $\"About$

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common denominator is (y+6)(y-6)
\n" ); document.write( "numerator is (y+1)(y-6)+5y=(y-3)(y+6)
\n" ); document.write( "y^2-5y-6+5y=y^2+3y-18.
\n" ); document.write( "Therefore,[ y^2-5y-6+5y]/(y^2-36)=[y^2+3y-18]/(y^2-36)
\n" ); document.write( " Since the denominator is the same on both sides, it cancels out.
\n" ); document.write( "-6=3y-18
\n" ); document.write( "3y=12
\n" ); document.write( "y=4
\n" ); document.write( "check
\n" ); document.write( "5/10+20/-20=(1/-2), and that is true. \n" ); document.write( "

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