document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1092543>Question 1092543</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find all of the points on the x-axis which are 2 units from the point (&#8722;1, 1).\r<BR>\n" );
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document.write( "Using the 2 points, (-1, 1) and (x, 0)\r<BR>\n" );
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document.write( "I have tried applying the distance formula, which gave me 4 = (-1 - x)^2 + 1, which I simplified to -(sqrt3 + 1), but the problem asks for 2 points, with the smaller and larger x-value. I am not even sure if my initial answer is the correct answer for one of the two points. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #707164 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=707164\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You were fine until the (-1-x)^2 part.  That is 1+2x+x^2.<BR>\n" );
document.write( "x^2+2x-3=0<BR>\n" );
document.write( "(x+3)(x-1)=0<BR>\n" );
document.write( "x=-3, 1<BR>\n" );
document.write( "The other way is to look just at the x-coordinate, -1.  Go two units up to +1, so (1, 1).  Go two units down to -3, so (-3, 1).<BR>\n" );
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