document.write( "Question 1092511: Sean is 20 and his brother is 12 how many years ago was sean three times as old as his brother \n" ); document.write( "
Algebra.Com's Answer #707134 by DrSteve(7)\"\" \"About 
You can put this solution on YOUR website!
I love problems like this! They're like wacky puzzles!\r
\n" ); document.write( "\n" ); document.write( "So lets set this one up:\r
\n" ); document.write( "\n" ); document.write( "what number, subtracted from BOTH THEIR AGES, will result in a number that makes Sean's age three times his brother's?\r
\n" ); document.write( "\n" ); document.write( "let's call Sean \"S\" and his brother \"B\" for the general equation, then we'll solve it. The number of years we're subtracting we'll just call \"x\".\r
\n" ); document.write( "\n" ); document.write( "S-x = 3(B - x)\r
\n" ); document.write( "\n" ); document.write( "in other words, Sean's age minus a number, is equal to 3 times Brother's age minus the same number.\r
\n" ); document.write( "\n" ); document.write( "We know Sean and Brother's ages, though, so let's plug them in!\r
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\n" ); document.write( "\n" ); document.write( "20 - x = 3(12 - x)\r
\n" ); document.write( "\n" ); document.write( "expanding the parenthetical gives us\r
\n" ); document.write( "\n" ); document.write( "20 - x = 36 - 3x\r
\n" ); document.write( "\n" ); document.write( "now add x to both sides\r
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\n" ); document.write( "\n" ); document.write( "20 = 36 - 2x\r
\n" ); document.write( "\n" ); document.write( "subtract 36 from both sides\r
\n" ); document.write( "\n" ); document.write( "-16 = -2x\r
\n" ); document.write( "\n" ); document.write( "divide both sides by -2\r
\n" ); document.write( "\n" ); document.write( "8 = x\r
\n" ); document.write( "\n" ); document.write( "...which is your answer!\r
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\n" ); document.write( "\n" ); document.write( "You can check it thusly:\r
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\n" ); document.write( "\n" ); document.write( "20 - 8 = 12
\n" ); document.write( "12 - 8 = 4\r
\n" ); document.write( "\n" ); document.write( "12/4 = 3 and there you go!
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