document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1092496>Question 1092496</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Larry Mitchell invested part of his $29,000 advance at 8% annual simple interest and the rest at 7% annual simple interest. If his total yearly interest from both accounts was 2,040, find the amount invested at each rate.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #707107 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=707107\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the part invested at 8% be x. Then,<BR>\n" );
document.write( "0.08x+0.07(29000-x) = 2040<BR>\n" );
document.write( "0.08x+2030-0.07x = 2040<BR>\n" );
document.write( "0.01x = 10<BR>\n" );
document.write( "x = 1000<BR>\n" );
document.write( "So, 1000 is invested at 8% and 29000-1000 = 28000 at 7%<BR>\n" );
document.write( "-----------------------------------------------<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "1000(0.08). . = 80<BR>\n" );
document.write( "28000(0.07). .= 1960<BR>\n" );
document.write( "--------------------<BR>\n" );
document.write( "Total . . . . = 2040 Correct </SPAN>\n" );
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