document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1092374>Question 1092374</A>: <I><SPAN STYLE=\"word-break: break-all;\"> maximize profit P = 40x + 30y<BR>\n" );
document.write( "constraints:<BR>\n" );
document.write( "1.	x + y <= 240<BR>\n" );
document.write( "2.	2x + y <= 320<BR>\n" );
document.write( "      x >= 0, y >= 0\r<BR>\n" );
document.write( "\n" );
document.write( "I need the answer by Using Big M Method..?? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #707059 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13209)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=707059\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br>The term \"Big M Method\" is not a standard term; it must be something your teacher or textbook uses.<br><BR>\n" );
document.write( "So I will go ahead and outline the process I use to solve problems like this.<br><BR>\n" );
document.write( "The intercepts of the first constraint line are (0,240) and (240,0); its slope is -1.<br><BR>\n" );
document.write( "The intercepts of the second constraint line are (0,320) and (160,0); its slope is -2.<br><BR>\n" );
document.write( "The two constraint lines intersect at (80,160).  (I will assume you know how to determine that....)<br><BR>\n" );
document.write( "So the possible points where we get maximum profit are (0,240), (80,160, and (160,0).<br><BR>\n" );
document.write( "If the slope of the constraint line is greater than the slope of the first constraint line (less negative; downward to the right but less steep than the first constraint line), then the maximum profit will be at the y-intercept of the first constraint line. <BR>\n" );
document.write( "If the slope of the constraint line is less than the slope of the second constraint line (more negative; steeper than the second constraint line), then the maximum profit will be at the x-intercept of the second constraint line.<BR>\n" );
document.write( "If the slope of the constraint line is between the slopes of the two constraint lines, then the maximum profit will be at the intersection of the two constraint lines.<br><BR>\n" );
document.write( "The slope of the constraint line is -4/3, which is between -1 and -2; so the maximum profit will be found at (80,160).  That maximum profit is 40x+30y = 3200+4800 = 8000. </SPAN>\n" );
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