document.write( "Question 1092371: The first difference of a sequence is the arithmetic sequence 3, 5, 7, 9, 11, ...... Find the first six terms of the original sequence in each of the following cases.\r
\n" ); document.write( "\n" ); document.write( "A. The first term in the original sequence is 3.
\n" ); document.write( "B. The sum of the first two terms in the original sequence is 11.
\n" ); document.write( "C. The fifth term in the original is 40.
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Algebra.Com's Answer #707036 by greenestamps(13200)\"\" \"About 
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This should be pretty straightforward, if you understand what the first differences of a sequence mean. The first differences being 3, 5, 7, 9, 11, ... means
\n" ); document.write( "3 is the difference between the 1st and 2nd terms;
\n" ); document.write( "5 is the difference between the 2nd and 3rd terms;
\n" ); document.write( "7 is the difference between the 3rd and 4th terms;
\n" ); document.write( "9 is the difference between the 4th and 5th terms; and
\n" ); document.write( "11 is the difference between the 5th and 6th terms

\n" ); document.write( "So....
\n" ); document.write( "A. If the first term of the sequence is 3, then the 2nd is 3+3 = 6; the 3rd is 6+5 = 11; the 4th is 11+7 = 18; the 5th is 18+9 = 27, and the 6th is 27+11 = 38.

\n" ); document.write( "B. If the sum of the first two terms is 11, and we know that the difference between the first two terms is 3, then we know the first two terms are 4 and 7. To get the 3rd through 6th terms, simply add the given differences between terms, as demonstrated in part A.

\n" ); document.write( "C. Given that the 5th term of the sequence is 40, you can find the 6th term by adding the known difference between the 5th and 6th terms; and you can find the 4th, 3rd, 2nd, and 1st terms by working backwards, subtracting the known differences between terms.
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