document.write( "Question 1092269: y2-8y+12x-8=0 what is the focus , directrix and the endpoints of latus rectum
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Algebra.Com's Answer #706952 by josgarithmetic(39620)\"\" \"About 
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\"y%5E2-8y%2B12x-8=0\"
\n" ); document.write( "\"y%5E2-8y=-12x%2B8\"
\n" ); document.write( "\"16\" will complete-the-square.
\n" ); document.write( "\"y%5E2-8y%2B16=-12x%2B8%2B16\"
\n" ); document.write( "\"%28y-4%29%5E2=-12x%2B24\"
\n" ); document.write( "\"highlight_green%28-12%28x-2%29=%28y-4%29%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "VERTEX (2,4)
\n" ); document.write( "FOCUS (-1,4)
\n" ); document.write( "DIRECTRIX x=5
\n" ); document.write( "EndPoints of LATUS RECTUM (-1,-2) and (-1,10)\r
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\n" ); document.write( "\n" ); document.write( "-
\n" ); document.write( "-12(-1-2)=(y-4)^2
\n" ); document.write( "36=(y-4)^2
\n" ); document.write( "y-4=0+- 6
\n" ); document.write( "y=4+- 6
\n" ); document.write( "y=-2 or y=10
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