document.write( "Question 1092302: The Sum of first 20th terms is 200 and Sum of next 10 terms is 400.What is the 40th term? \n" ); document.write( "
Algebra.Com's Answer #706926 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!

You don't say so, but I will assume this is an arithmetic sequence....

\n" ); document.write( "In any arithmetic sequence, the sum of n terms is n times the average of the first and last terms.

\n" ); document.write( "The sum of the first 20 terms is 20 times the average of the first and 20th terms. If the first term is a and the common difference is d, then the 20th term is a+19d. Since your problem says the sum of the first 20 terms is 200,
\n" ); document.write( "\"20%28a%2B%28a%2B19d%29%29%2F2+=+200\"
\n" ); document.write( "\"10%282a%2B19d%29+=+200\"
\n" ); document.write( "\"2a%2B19d+=+20\" (1)

\n" ); document.write( "Also in your problem the sum of the next 10 terms (terms 21 through 30) is 400. The 21st term is a+20d; the 30th is a+29d. The sum of those 10 terms is
\n" ); document.write( "\"10%28%28a%2B20d%29%2B%28a%2B29d%29%29%2F2+=+400\"
\n" ); document.write( "\"2a%2B49d+=+80\" (2)

\n" ); document.write( "Subtract equation (1) from equation (2) and solve for d; then plug that value for d in either (1) or (2) to solve for a.

\n" ); document.write( "\"30d+=+60\"
\n" ); document.write( "\"d+=+2\"
\n" ); document.write( "\"2a%2B19%282%29+=+20\"
\n" ); document.write( "\"2a%2B38+=+20\"
\n" ); document.write( "\"2a+=+-18\"
\n" ); document.write( "\"a+=+-9\"

\n" ); document.write( "We are to find the 40th term, which is a+39d:
\n" ); document.write( "\"-9%2B40%282%29+=+-9%2B80+=+71\"

\n" ); document.write( "The 40th term is 71.

\n" ); document.write( "Oops! I said the 40th term is a+39d, but then I calculated a+40d.

\n" ); document.write( "The 40th term is a+39d:
\n" ); document.write( "\"-9%2B39%282%29+=+-9%2B78+=+69\"

\n" ); document.write( "So the 40th term is 69, which is one of your answer choices.\r
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