document.write( "Question 1092302: The Sum of first 20th terms is 200 and Sum of next 10 terms is 400.What is the 40th term? \n" ); document.write( "
Algebra.Com's Answer #706926 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! You don't say so, but I will assume this is an arithmetic sequence.... \n" ); document.write( "In any arithmetic sequence, the sum of n terms is n times the average of the first and last terms. \n" ); document.write( "The sum of the first 20 terms is 20 times the average of the first and 20th terms. If the first term is a and the common difference is d, then the 20th term is a+19d. Since your problem says the sum of the first 20 terms is 200, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Also in your problem the sum of the next 10 terms (terms 21 through 30) is 400. The 21st term is a+20d; the 30th is a+29d. The sum of those 10 terms is \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Subtract equation (1) from equation (2) and solve for d; then plug that value for d in either (1) or (2) to solve for a. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "We are to find the 40th term, which is a+39d: \n" ); document.write( " \n" ); document.write( "The 40th term is 71. \n" ); document.write( "Oops! I said the 40th term is a+39d, but then I calculated a+40d. \n" ); document.write( "The 40th term is a+39d: \n" ); document.write( " \n" ); document.write( "So the 40th term is 69, which is one of your answer choices.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |