document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=97031>Question 97031</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Bob fenced in a rectangular garden in his yard.  The length of the rectangle is 6 feet longer than the width and the perimeter is 104 feet.  What is the width of the rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #70692 by </B><A HREF=/tutors/aboutme.mpl?userid=guitarguy23><B>guitarguy23(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=guitarguy23><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=70692\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Honestly, im not how to solve it correctly. But heres what i do have.<BR>\n" );
document.write( "Go ahead and divide 104 by 4 (sides). You get 26<BR>\n" );
document.write( "Since the legnth is 6 feet longer, just add 6 to the legnth and subtract 6 from the width, you end up with the legnth of both sides being 32, and the width of both sides being 20\r<BR>\n" );
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document.write( "Check:\r<BR>\n" );
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document.write( "Perimiter is adding the 4 sides together.<BR>\n" );
document.write( "20+20=40<BR>\n" );
document.write( "32+32=64<BR>\n" );
document.write( "64+40=104 </SPAN>\n" );
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