document.write( "Question 1092312: Find the y-intercept of the line with gradient -3 that is tangential to the parabola
\n" ); document.write( "y = 2x^2-5x + 1.
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Algebra.Com's Answer #706909 by josmiceli(19441)\"\" \"About 
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Find the derivative y'
\n" ); document.write( "\"+y%5B1%5D+=+4x+-+5+\"
\n" ); document.write( "You are given y' = -3
\n" ); document.write( "\"+4x+-+5+=+-3+\"
\n" ); document.write( "\"+4x+=+2+\"
\n" ); document.write( "\"+x+=+1%2F2+\"
\n" ); document.write( "Now find \"+y+\" on the parabola
\n" ); document.write( "where slope = \"+-3+\"
\n" ); document.write( "\"+y+=+2%2A%281%2F2%29%5E2+-+5%2A%281%2F2%29+%2B+1+\"
\n" ); document.write( "\"+y+=+1%2F2+-+5%2F2+%2B+2%2F2+\"
\n" ); document.write( "\"+y+=+-1+\"
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\n" ); document.write( "The line is tangent to the parabola at the point ( 1/2, -1 )
\n" ); document.write( "The slope intercept form is:
\n" ); document.write( "\"+y+=+m%2Ax+%2B+b+\"
\n" ); document.write( "where \"+b+\" is the y-intercept
\n" ); document.write( "\"+-1+=+%28-3%29%2A%281%2F2%29+%2B+b+\"
\n" ); document.write( "\"+-1+=+-3%2F2+%2B+b+\"
\n" ); document.write( "\"+b+=+1%2F2+\"
\n" ); document.write( "The y-intercept is at ( 0, 1/2 )
\n" ); document.write( "------------------------------
\n" ); document.write( "Check:
\n" ); document.write( "Here's the plot of parabola and straight line:
\n" ); document.write( "\"+graph%28+400%2C+400%2C+-6%2C+6%2C+-6%2C+6%2C+2x%5E2+-+5x+%2B+1%2C+-3x+%2B+1%2F2+%29+\"
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