document.write( "Question 1092278: if S2 = 10, S10 = 2 then what is a1, d (Arithmetic Sequence) \n" ); document.write( "
Algebra.Com's Answer #706884 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Using a for the first term and d for the common difference...

\n" ); document.write( "S(2) = a + (a+d) = 2a+d = 10

\n" ); document.write( "S(10) = a + (a+d) + (a+2d) + ... + (a+9d) = 10a+45d

\n" ); document.write( "So we know
\n" ); document.write( "\"2a%2Bd+=+10\"
\n" ); document.write( "\"10a%2B45d+=+2\"

\n" ); document.write( "Multiply the first equation by 5 and subtract the second equation to eliminate variable a, then solve for d.

\n" ); document.write( "\"10a%2B5d+=+50\"
\n" ); document.write( "\"40d+=+-48\"
\n" ); document.write( "\"d+=+-48%2F40+=+-1.2\"

\n" ); document.write( "The common difference, d, is -1.2. Plug this value into one of the earlier equations to solve for a.

\n" ); document.write( "\"2a%2B%28-1.2%29+=+10\"
\n" ); document.write( "\"2a+=+11.2\"
\n" ); document.write( "\"a+=+5.6\"

\n" ); document.write( "The first term, a is 5.6.

\n" ); document.write( "Answers: first term is 5.6; common difference is -1.2.
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