document.write( "Question 1092172: Ref. Question 1092130:\r
\n" ); document.write( "\n" ); document.write( "The area of FRAME, not total area, is 470 sq. in. Sorry for the error.
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Algebra.Com's Answer #706767 by greenestamps(13203)\"\" \"About 
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I picture the frame as consisting of a 5-inch wide strip on each of the four edges of the picture, plus four 5x5 inch squares in the corners. Then if x is the width of the picture and x+7 is the length,

\n" ); document.write( "\"5%28x%2Bx%2B7%2Bx%2Bx%2B7%29%2B4%285%2A5%29+=+470\"
\n" ); document.write( "\"5%284x%2B14%29%2B100+=+470\"
\n" ); document.write( "\"20x%2B170+=+470\"
\n" ); document.write( "\"20x+=+300\"
\n" ); document.write( "\"x+=+15\"

\n" ); document.write( "The dimensions of the picture are 15x22; the dimensions with the frame are 25x32.

\n" ); document.write( "Checking the answer...

\n" ); document.write( "\"25%2A32+=+800\" (picture plus frame)
\n" ); document.write( "\"15%2A22+=+330\" (picture only)
\n" ); document.write( "\"800-330+=+470\" (frame only)
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