document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1092179>Question 1092179</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The dimension of a rectangle are such that it's length is 5 in. more than its width. If the length were doubled and if the width were decreased by 5 in. the area would be increased by 162 in^2. What are the length and width of the rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #706761 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=706761\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> width=w<BR>\n" );
document.write( "length=w+5 units inches<BR>\n" );
document.write( "Area, A1= w(w+5)=w^2+5w<BR>\n" );
document.write( "A2=2(w+5)(w-5)=2w^2-50<BR>\n" );
document.write( "w^2+5w+162=2w^2-50<BR>\n" );
document.write( "0=w^2-5w-212<BR>\n" );
document.write( "w=(1/2)(5+/- sqrt (25+848); sqrt 873=29.55<BR>\n" );
document.write( "positive root is w=17.28 inches ANSWER<BR>\n" );
document.write( "length is 22.28 inches ANSWER<BR>\n" );
document.write( "area is 385<BR>\n" );
document.write( "double length and get 44.56<BR>\n" );
document.write( "decrease width by 5 and get 12.28<BR>\n" );
document.write( "area is 547.20, 162 more with rounding error. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );