document.write( "Question 97107: I need help solving this inequality in interval notation. Thank you.\r
\n" ); document.write( "\n" ); document.write( "\"+%28x%2B12%29%28x-2%29+%2F+%28x-1%29+\" ≥ 0
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Algebra.Com's Answer #70675 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
[(x+12)(x-2) / (x-1)] >= 0
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\n" ); document.write( "Solve the EQUALITY:
\n" ); document.write( "The fraction is 0 when the numerator is zero.
\n" ); document.write( "Zero when x=-12 or when x=2
\n" ); document.write( "Draw a line and plot x=-12 and x=2 on it.
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\n" ); document.write( "Also plot the point x-1 since x cannot be 1.
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\n" ); document.write( "That line now has four intervals.
\n" ); document.write( "Check a test point in each of the four intervals to find the INEQUALITY solution intervals for [(x+12)(x-2) / (x-1)] > 0:
\n" ); document.write( "Note: I will just track the signs of the factors.
\n" ); document.write( "In (-inf,-12) select x=-13 : (-)(-)/- < 0 so no solution in that interval
\n" ); document.write( "In (-12,1) select x=0: (+)(-)/(-) >0; that interval is part of the solution
\n" ); document.write( "In (1,2) select x=3/2; (+)(-)/(+)<0; so no solution in that interval
\n" ); document.write( "In (2,+inf) select x=3: (+)(+)/(+)>0; that interval is part of the solution
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\n" ); document.write( "Final solution:
\n" ); document.write( "[-12,1),[2,+inf)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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