document.write( "Question 97107: I need help solving this inequality in interval notation. Thank you.\r
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Algebra.Com's Answer #70675 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! [(x+12)(x-2) / (x-1)] >= 0 \n" ); document.write( "------------------------------ \n" ); document.write( "Solve the EQUALITY: \n" ); document.write( "The fraction is 0 when the numerator is zero. \n" ); document.write( "Zero when x=-12 or when x=2 \n" ); document.write( "Draw a line and plot x=-12 and x=2 on it. \n" ); document.write( "--------------- \n" ); document.write( "Also plot the point x-1 since x cannot be 1. \n" ); document.write( "--------------- \n" ); document.write( "That line now has four intervals. \n" ); document.write( "Check a test point in each of the four intervals to find the INEQUALITY solution intervals for [(x+12)(x-2) / (x-1)] > 0: \n" ); document.write( "Note: I will just track the signs of the factors. \n" ); document.write( "In (-inf,-12) select x=-13 : (-)(-)/- < 0 so no solution in that interval \n" ); document.write( "In (-12,1) select x=0: (+)(-)/(-) >0; that interval is part of the solution \n" ); document.write( "In (1,2) select x=3/2; (+)(-)/(+)<0; so no solution in that interval \n" ); document.write( "In (2,+inf) select x=3: (+)(+)/(+)>0; that interval is part of the solution \n" ); document.write( "=========== \n" ); document.write( "Final solution: \n" ); document.write( "[-12,1),[2,+inf) \n" ); document.write( "================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |