document.write( "Question 97110: Please help me solve this inequality:\r
\n" ); document.write( "\n" ); document.write( "\"+x%5E2-5x-6+\" ≤ 0
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Algebra.Com's Answer #70674 by mathslover(157)\"\" \"About 
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\n" ); document.write( "x^2 -5x -6 <=0\r
\n" ); document.write( "\n" ); document.write( "factorising the left hand side of the expression \r
\n" ); document.write( "\n" ); document.write( "(x-6)(x+1) <=0\r
\n" ); document.write( "\n" ); document.write( "the product of 2 numbers will be <=0 when one is >=0 and the other <=0\r
\n" ); document.write( "\n" ); document.write( "case 1
\n" ); document.write( " x-6 <=0 and x+1 >=0\r
\n" ); document.write( "\n" ); document.write( "gives x<=6 and x>= -1\r
\n" ); document.write( "\n" ); document.write( "Solution set is [-1,6]
\n" ); document.write( "ie -1<=x<=6\r
\n" ); document.write( "\n" ); document.write( "case 2
\n" ); document.write( " x-6 >=0 and x+1 <=0
\n" ); document.write( "gives
\n" ); document.write( " x>=6 and x<= -1
\n" ); document.write( "which does not hold true for any x \r
\n" ); document.write( "\n" ); document.write( "hence the only solution is [-1,6]
\n" ); document.write( "ie -1<=x<=6\r
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