document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1092148>Question 1092148</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Using synthetic division, what is the quotient and the remainder when (2x^3-3x+1) is divided by (x+1)?\r<BR>\n" );
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document.write( "I tried this one myself too, but I came up with 2x^2+3+6/x-1 and that's apparently wrong... If somebody could place some solutions with this please, that'd be great, thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #706693 by </B><A HREF=/tutors/aboutme.mpl?userid=ikleyn><B>ikleyn(52797)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ikleyn><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ikleyn><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=706693\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "The remainder is the value of the polynomial at x= -1, i.e.\r<BR>\n" );
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document.write( "2*(-1)^3 - 3*(-1) + 1 = 2*(-1) + 3 + 1 = -2 + 3 + 1 = 2.\r<BR>\n" );
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document.write( "It can not be &nbsp;6, &nbsp;as @josgarithmetic states // stated in his original version . . . which he quickly and untraceably replaced after my notice.\r<BR>\n" );
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document.write( "His solution was  &nbsp;&nbsp;<U>W R O N G</U>&nbsp;,  &nbsp;&nbsp;&nbsp;a&nbsp;s &nbsp;&nbsp;&nbsp;u&nbsp;s&nbsp;u&nbsp;a&nbsp;l.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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