document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1092135>Question 1092135</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A bag contains a total of 200 quarters and dimes. If the total value of the bags contents is $41.00.How many quarters and how many dimes are in the bag? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #706685 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13327)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=706685\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br>Here is a solution that combines informal algebra with logical analysis... instead of using purely formal algebra.<br><BR>\n" );
document.write( "Suppose all 200 coins were quarters.  The total value would be $50.<br><BR>\n" );
document.write( "But the total is only $41.  That's $9 short of the total we would get with all quarters.<br><BR>\n" );
document.write( "So let's start taking away quarters and replacing them with dimes. Each time we do that, the total value of the coins is reduced by 15 cents -- because the quarter was worth 25 cents and we replaced it with a dime worth only 10 cents.<br><BR>\n" );
document.write( "But if we need to get the $50 down to $41, we need to reduce the value of the coins by $9, or 900 cents.  If each time we replace a quarter with a dime we reduce the total value by 15 cents, then the number of quarters we need to replace is 900/15 = 60.<br><BR>\n" );
document.write( "And when we have replaced 60 quarters with dimes, we find we have 140 quarters and 60 dimes. </SPAN>\n" );
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