document.write( "Question 1092130: A framed picture is 7 inches longer than wide. The width of frame is 5 inches. Total area is 470 square inches. Determine outside dimensions of framed picture. \r
\n" ); document.write( "\n" ); document.write( "Area = length * width \r
\n" ); document.write( "\n" ); document.write( "w = width \r
\n" ); document.write( "\n" ); document.write( "l = w + 7 \r
\n" ); document.write( "\n" ); document.write( "Not sure how to include frame width.\r
\n" ); document.write( "\n" ); document.write( "(w + 7)(w) = 470 \r
\n" ); document.write( "\n" ); document.write( "w^2 + 7w = 470 \r
\n" ); document.write( "\n" ); document.write( "Not sure from here. Non-homework.
\n" ); document.write( "

Algebra.Com's Answer #706680 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!

Since the problem says the total area is 470 square inches, instead of APPROXIMATELY 470 square inches, I would assume the dimensions of the picture are whole numbers.

\n" ); document.write( "With a 5 inch border, the dimensions of the picture plus frame are (length of picture) plus 10 and (width of picture) plus 10.

\n" ); document.write( "Since we want whole number measurements, we look for ways to write 470 as the product of two whole numbers, each of which must be at least 10.

\n" ); document.write( "But the only way to do that is 470 = 47*10, which means the dimensions of the picture itself would be 37 by 0 -- which makes no sense.

\n" ); document.write( "So I suspect there is a problem with the numbers you show for the problem.
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