document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1092138>Question 1092138</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two planes which are 3650 miles apart fly towards each other. Their speeds differ by 80 mph. If they pass each other in 5 hours what is the speed of each?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #706678 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13206)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=706678\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br>The distance of 3650 miles is covered by the two planes together in 5 hours, so the combined speeds of the two planes is 3650/5 = 730.<br><BR>\n" );
document.write( "You can use formal algebra if you want to find the speed of each plane, knowing that their combined speed is 730 mph and that one plane's speed is 80 mph greater then the other's.<br><BR>\n" );
document.write( "Or you can subtract the \"extra\" 80 mph of the faster plane to find that the two planes flying at the same speed would have a combined speed of 730-80=650 mph.  Then half of that for the slow plane is 325 mph, making the speed of the faster plane 325+80=405 mph. </SPAN>\n" );
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