document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1092113>Question 1092113</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Theresa earns a full athletic scholarship for college so her parents have given her the $20.000 they had saved to pay for her college tuition. she decides to invest that money with an overall goal of earning 11% interest. she wants to put some of the money in a low-risk investment that has been earning 8% a year and the rest of the money in a medium risk investment that typically earns 12% a year. how much money should she put in each investment to reach her goal? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #706645 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=706645\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x is invested at 8%, so interest per year is 0.08x.<BR>\n" );
document.write( "20000-x is the rest invested at 12%, so interest per year is (20000-x)(0.12)=2400-0.12x<BR>\n" );
document.write( "This has to equal the amount of interest gained for 20000*0.11=2200<BR>\n" );
document.write( "Therefore, 0.08x+2400-0.12x=2200<BR>\n" );
document.write( "-0.04x=-200<BR>\n" );
document.write( "multiply both sides by -25<BR>\n" );
document.write( "x=$5000 @8% or $400<BR>\n" );
document.write( "20000-x=$15000@12%=$1800<BR>\n" );
document.write( "They add to $2200, which is 11% of $20000. </SPAN>\n" );
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