document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1092089>Question 1092089</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jane took 15 min to drive her boat upstream to water-ski at her favorite spot. Coming back later in the day, at the same boat speed took her 10 min. If the current in that part of the river is 4 km per hr, what was her boat speed in still water? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #706603 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=706603\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let s be the speed of Jane's boat in still water. Then:<BR>\n" );
document.write( ".25(s-4)=.2(s+4)  (.25=1/4 hour=15 min; .2=1/5 hr=10 min)<BR>\n" );
document.write( ".25s-1=.2s+.8<BR>\n" );
document.write( ".05s=1.8<BR>\n" );
document.write( "s=36<BR>\n" );
document.write( "Jane's boat goes 36 kmh in still water <BR>\n" );
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