document.write( "Question 1092062: The UP Rowing team can row the 18-kilometer portion of the Agusan river in 3 hours downstream and 6 hours upstream, How fast is their boat and the rate of the current of the river? \n" ); document.write( "
Algebra.Com's Answer #706587 by addingup(3677) You can put this solution on YOUR website! Speed = distance/time \n" ); document.write( "Let s (speed) be the speed of the boat and c (current) the speed of the current \n" ); document.write( ": \n" ); document.write( "S(upstream) = s-c \n" ); document.write( "S(downstream) = s+c \n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~ \n" ); document.write( "Upstream data: \n" ); document.write( "d = 18 \n" ); document.write( "t = 6 \n" ); document.write( "18/6 = 3km/h <---- this is the speed of the boat going upstream. \n" ); document.write( ". . . . . . . . . . . . . . . . . \n" ); document.write( "Downstream data: \n" ); document.write( "d = 18 \n" ); document.write( "t = 3 \n" ); document.write( "18/3 = 6km/h <--- this is the speed of the boat going downstream. \n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ \n" ); document.write( "Summarizing: \n" ); document.write( "S(up) : s-c = 3km/h \n" ); document.write( "S(dwn): s+c = 6km/h \n" ); document.write( ". . . . . . . . . . . . . . . . . . . . \n" ); document.write( "Let's find the speed of the current: \n" ); document.write( "S(up) : s = 3+c \n" ); document.write( "S(dwn): s = 6-c \n" ); document.write( "3+c = 6-c \n" ); document.write( "2c = 3 \n" ); document.write( "c = 1.5 <-- this is the speed of the current. \n" ); document.write( "Substitute in the equation to find the speed of the boat in still water: \n" ); document.write( "3+1.5 = 6-1.5 = 4.5 <--- this is the speed of the boat in still water. \n" ); document.write( " \n" ); document.write( " |