document.write( "Question 1092062: The UP Rowing team can row the 18-kilometer portion of the Agusan river in 3 hours downstream and 6 hours upstream, How fast is their boat and the rate of the current of the river? \n" ); document.write( "
Algebra.Com's Answer #706587 by addingup(3677)\"\" \"About 
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Speed = distance/time
\n" ); document.write( "Let s (speed) be the speed of the boat and c (current) the speed of the current
\n" ); document.write( ":
\n" ); document.write( "S(upstream) = s-c
\n" ); document.write( "S(downstream) = s+c
\n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~
\n" ); document.write( "Upstream data:
\n" ); document.write( "d = 18
\n" ); document.write( "t = 6
\n" ); document.write( "18/6 = 3km/h <---- this is the speed of the boat going upstream.
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\n" ); document.write( "Downstream data:
\n" ); document.write( "d = 18
\n" ); document.write( "t = 3
\n" ); document.write( "18/3 = 6km/h <--- this is the speed of the boat going downstream.
\n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
\n" ); document.write( "Summarizing:
\n" ); document.write( "S(up) : s-c = 3km/h
\n" ); document.write( "S(dwn): s+c = 6km/h
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\n" ); document.write( "Let's find the speed of the current:
\n" ); document.write( "S(up) : s = 3+c
\n" ); document.write( "S(dwn): s = 6-c
\n" ); document.write( "3+c = 6-c
\n" ); document.write( "2c = 3
\n" ); document.write( "c = 1.5 <-- this is the speed of the current.
\n" ); document.write( "Substitute in the equation to find the speed of the boat in still water:
\n" ); document.write( "3+1.5 = 6-1.5 = 4.5 <--- this is the speed of the boat in still water.
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