document.write( "Question 1092061: Five years ago,David was three times as old as his son,Mike.Five years from now,David's age will be twice his son's age.Find their present ages.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "emergency
\n" ); document.write( "

Algebra.Com's Answer #706568 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Five years ago,
\n" ); document.write( "\"D-5=3%28M-5%29\"
\n" ); document.write( "\"D-5=3M-15\"
\n" ); document.write( "1.\"D-3M=-10\"
\n" ); document.write( "Five years from now,
\n" ); document.write( "\"D%2B5=2%28M%2B5%29\"
\n" ); document.write( "\"D%2B5=2M%2B10\"
\n" ); document.write( "2.\"D-2M=5\"
\n" ); document.write( "Subtract 1 from 2,
\n" ); document.write( "\"D-2M-D%2B3M=5-%28-10%29\"
\n" ); document.write( "\"M=15\"
\n" ); document.write( "Use either equation to solve for D.
\n" ); document.write( "
\n" ); document.write( "
\n" );