document.write( "Question 1091909: Two darts are thrown at the board below, if you get the same number twice, the second dart is removed and re-thrown. If you get 10 points or more, you win a prize.
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\n" ); document.write( "1) If a 4 was scored with the first dart, find P(Win)
\n" ); document.write( "2)If a 3 was scored with the first dart, find P(Win)
\n" ); document.write( "3)If a 2 was scored with the first dart, find P(Win)
\n" ); document.write( "4)If an 8 was scored with the first dart, find P(Lose)
\n" ); document.write( "Answer as a percentage- round to 1 d.p
\n" ); document.write( "Can someone please help me?
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Algebra.Com's Answer #706553 by greenestamps(13203)\"\" \"About 
You can put this solution on YOUR website!

It took me several times looking at this problem before I could make sense out of it. I think I understand now....

\n" ); document.write( "The dart board is a 4x4 array of squares with the numbers you show in the squares. You throw two darts; if the second one gets the same number as the first, you throw the second dart again. You win if the sum of the two numbers is 10 or more.

\n" ); document.write( "(1) Find P(win) if the first dart is 4.

\n" ); document.write( "There is only one 4 on the board, so there are 15 squares you can hit with the second dart. Of those 15, 3 have numbers large enough (6 or greater) that will give a combined score of 10 or more. So P(win) = 3/15 = 1/5 = 20%

\n" ); document.write( "(2) Find P(win) if the first dart is 3.

\n" ); document.write( "There are two 3's on the board, so there are 14 squares you can hit with the second dart. Of those 14, 2 have numbers large enough (7 or greater) that will give a combined score of 10 or more. So P(win) = 2/14 = 1/7 = 14.3%

\n" ); document.write( "(3) Find P(win) if the first dart is 2.

\n" ); document.write( "There are five 2's on the board, so there are 11 squares you can hit with the second dart. Of those 11, only 1 has a number large enough (8 or greater) that will give a combined score of 10 or more. So P(win) = 1/11 = 9.1%

\n" ); document.write( "(4) Find P(lose) if the first dart is 8.

\n" ); document.write( "There is only one 8 on the board, so there are 15 squares you can hit with the second dart. This time you want to lose, meaning you want a sum less than 10; of the 15 squares you can hit, 3 have a number small enough (it must be 1) that will give a combined score of less than 10. So P(lose) = 3/15 = 1/5 = 20%
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