document.write( "Question 1092026: A board, 39 cm long is cut into three pieces such that the second piece is twice as long as the first and the third is 4 cm longer than the second. Find the length of the shorter piece. \n" ); document.write( "
Algebra.Com's Answer #706525 by addingup(3677)\"\" \"About 
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3 pieces: x, y, z
\n" ); document.write( "the second, y, is 2x or y = 2x
\n" ); document.write( "the 3rd, z, is 4cm longer than y, or z = y+4
\n" ); document.write( "x+y+z = 39 substituting:
\n" ); document.write( "x+2x+y+4 = 39 OK, this won't work because x and y don't mix. But since we know that y = 2x, we can add 4 to this y-equivalent, like this:
\n" ); document.write( "x+2x+2x+4 = 39
\n" ); document.write( "Now we've got it. Add up the x:
\n" ); document.write( "5x+4 = 39
\n" ); document.write( "5x = 35
\n" ); document.write( "x = 7
\n" ); document.write( "-------------------------------------
\n" ); document.write( "Check:
\n" ); document.write( "x = 7
\n" ); document.write( "y = 2x = 14
\n" ); document.write( "z = 2x+4 = 18
\n" ); document.write( "7+14+18 = 39 Correct
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