document.write( "Question 1092025: A board, 39 cm long is cut into three pieces such that the second piece is twice as long as the first and the third is 4 cm longer than the second. \n" ); document.write( "
Algebra.Com's Answer #706524 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
x, y, z - first second third\r
\n" ); document.write( "\n" ); document.write( "(Exact translation from written description):
\n" ); document.write( "\"system%28y=2x%2Cz=y%2B4%29\"\r
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\n" ); document.write( "\n" ); document.write( "Put x and z in terms of y and then avoid using them as variables.\r
\n" ); document.write( "\n" ); document.write( "\"system%28x=y%2F2%2Cz=y%2B4%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"y%2F2%2By%2B%28y%2B4%29=39\"-----one equation, one variable.\r
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\n" ); document.write( "\n" ); document.write( "\"y%2F2%2B2y%2B4=39\"\r
\n" ); document.write( "\n" ); document.write( "\"y%2F2%2B2y=35\"\r
\n" ); document.write( "\n" ); document.write( "\"y%2B4y=70\"\r
\n" ); document.write( "\n" ); document.write( "\"5y=70\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28y=14%29\"--------You can use this length to evaluate the other two lengths.\r
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\n" ); document.write( "\n" ); document.write( "x=y/2,x=7;
\n" ); document.write( "z=y+4=14+4=18
\n" ); document.write( "check: x+y+z=39?
\n" ); document.write( "7+14+18=21+18=39.
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