document.write( "Question 1091996: A freight train travels north at a rate of 50mph. A passenger train leaves 4 hours later on a parallel track and travels north at 90mph. How long will it take the passenger train to catch up to the freight train? \n" ); document.write( "
Algebra.Com's Answer #706492 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! The head start of the freight train in miles is: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "--------------------- \n" ); document.write( "Start a stopwatch when the passenger train leaves. \n" ); document.write( "Let \n" ); document.write( "passenger train catches up with the freight train \n" ); document.write( "Let \n" ); document.write( "travels until it catches up with the freight train \n" ); document.write( "----------------------------------------------- \n" ); document.write( "Equation for the pasenger train: \n" ); document.write( "(1) \n" ); document.write( "Equation for the freight train: \n" ); document.write( "(2) \n" ); document.write( "--------------------------------- \n" ); document.write( "Plug (1) into (2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "The passenger train will catch the freight train in 5 hrs \n" ); document.write( "---------------------- \n" ); document.write( "check: \n" ); document.write( "(1) \n" ); document.write( "(1) \n" ); document.write( "and \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "(2) \n" ); document.write( "OK \n" ); document.write( " |