document.write( "Question 1091996: A freight train travels north at a rate of 50mph. A passenger train leaves 4 hours later on a parallel track and travels north at 90mph. How long will it take the passenger train to catch up to the freight train? \n" ); document.write( "
Algebra.Com's Answer #706492 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
The head start of the freight train in miles is:
\n" ); document.write( "\"+d%5B1%5D+=+50%2A4+\"
\n" ); document.write( "\"+d%5B1%5D+=+200+\" mi
\n" ); document.write( "---------------------
\n" ); document.write( "Start a stopwatch when the passenger train leaves.
\n" ); document.write( "Let \"+t+\" = time in hrs on the stopwatch when the
\n" ); document.write( "passenger train catches up with the freight train
\n" ); document.write( "Let \"+d+\" = distance in miles the passenger train
\n" ); document.write( "travels until it catches up with the freight train
\n" ); document.write( "-----------------------------------------------
\n" ); document.write( "Equation for the pasenger train:
\n" ); document.write( "(1) \"+d+=+90t+\"
\n" ); document.write( "Equation for the freight train:
\n" ); document.write( "(2) \"+d+-+200+=+50t+\"
\n" ); document.write( "---------------------------------
\n" ); document.write( "Plug (1) into (2)
\n" ); document.write( "(2) \"+90t+-+200+=+50t+\"
\n" ); document.write( "(2) \"+40t+=+200+\"
\n" ); document.write( "(2) \"+t+=+5+\"
\n" ); document.write( "The passenger train will catch the freight train in 5 hrs
\n" ); document.write( "----------------------
\n" ); document.write( "check:
\n" ); document.write( "(1) \"+d+=+90%2A5+\"
\n" ); document.write( "(1) \"+d+=+450+\"
\n" ); document.write( "and
\n" ); document.write( "(2) \"+d+-+200+=+50%2A5+\"
\n" ); document.write( "(2) \"+d+=+200+%2B+250+\"
\n" ); document.write( "(2) \"+d+=+450+\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );