document.write( "Question 1091928: A Canadian Goose and Great Blue Heron took off in opposite directions. The goose flew at 20 mph, and the heron flew at 10 mph. When they landed, they were 180 miles apart. Altogether, they flew for 14 hours. How long did each bird fly?\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #706426 by ikleyn(52878) $\"\"$ $\"About$

You can put this solution on YOUR website!
.
\n" ); document.write( "

\r\n" );
document.write( "Let x be the time for Canadian Goose (CG), in hours.\r\n" );
document.write( "\r\n" );
document.write( "Then the time for the Great Blue Heron (GBH) is (14 - x) hours.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "The distance equation is \r\n" );
document.write( "\r\n" );
document.write( "20*x + 10*(14-x) = 180.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Simplify and solve for x:\r\n" );
document.write( "\r\n" );
document.write( "20x + 140 - 10x = 180,\r\n" );
document.write( "\r\n" );
document.write( "20x - 10x = 180 - 140,\r\n" );
document.write( "\r\n" );
document.write( "10x = 40,\r\n" );
document.write( "\r\n" );
document.write( "x =  = 4.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Answer.  GC time is 4 hours.   GBH time is 14-4 = 10 hours.\r\n" );
document.write( "

\r
\n" ); document.write( "\n" ); document.write( "Solved.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );