document.write( "Question 1091924: The line 3x+2y = 24 meets y- axis at A and x- axis at B. The perpendicular bisector of AB meets the line
\n" ); document.write( "through (0, -1 ) parallel to x- axis at C. Then area of the triangle ABC is
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Algebra.Com's Answer #706425 by Fombitz(32388)\"\" \"About 
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At A,\"y=0\",
\n" ); document.write( "\"3x%2B2%280%29=24\"
\n" ); document.write( "\"x=8\"
\n" ); document.write( "A:(8,0)
\n" ); document.write( "At B, \"x=0\"
\n" ); document.write( "\"3%280%29%2B2y=24\"
\n" ); document.write( "\"y=12\"
\n" ); document.write( "B:(0,12)
\n" ); document.write( "The slope of AB is,
\n" ); document.write( "\"m=%2812-0%29%2F%280-8%29=-12%2F8=-3%2F2\"
\n" ); document.write( "The perpendicular bisector to AB would have a slope,
\n" ); document.write( "\"m%2A%28-3%2F2%29=-1\"
\n" ); document.write( "\"m=2%2F3\"
\n" ); document.write( "and it goes through (0,-1),
\n" ); document.write( "\"y-%28-1%29=%282%2F3%29%28x-0%29\"
\n" ); document.write( "\"y%2B1=%282%2F3%29x\"
\n" ); document.write( "So now is (0,-1) point C?
\n" ); document.write( "Here's a picture of the perpendicular bisector to AB through (0,-1) but now unless (0,-1) is point C, I'm confused as to where C would be.
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\n" ); document.write( "If that's the case,
\n" ); document.write( "\"A=%281%2F2%29%2812-%28-1%29%29%288%29\"
\n" ); document.write( "\"A=52\"
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\n" ); document.write( "If not, please provide additional information.\r
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