document.write( "Question 1091902: P,Q and R are each mixtures of red and white paint.
\n" ); document.write( "The percentage by volume of red paint in P is 30%.
\n" ); document.write( "The percentage by volume of red paint in Q is 20%.
\n" ); document.write( "The mixtures P,Q,and R are combined in the proportion 12:5:3 respectively.
\n" ); document.write( " If the resulting mixture contains 25% by volume of red paint, what percentage
\n" ); document.write( "by volume of mixture R is red paint ?\r
\n" ); document.write( "\n" ); document.write( " The answer was given as 13 and 1/3 % . Just asking about the steps to arrive
\n" ); document.write( " at this answer. Thank you, Melton Ellis mellis7379@gmail.com
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #706399 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!

If P, Q, and R are mixed in the ratio 12:5:3, then we can let the amounts of P, Q, and R be represented by 12x, 5x, and 3x; that makes 20x the total amount of the mixture.

\n" ); document.write( "Let y be the unknown percentage of R. (To avoid having to use fractions, I will work the problem using percents....) Then the amounts of red paint in the three ingredients are
\n" ); document.write( "P: 30(12x)
\n" ); document.write( "Q: 20(5x)
\n" ); document.write( "R: y(3x)

\n" ); document.write( "Then the total amount of red paint in the mixture is
\n" ); document.write( "\"30%2812x%29%2B20%285x%29%2By%283x%29+=+360x%2B100x%2B3yx+=+460x%2B3yx\"

\n" ); document.write( "Then since the total amount of mixture is 20x, the percentage of red paint is
\n" ); document.write( "\"%28460x%2B3yx%29%2F20x+=+%28460%2B3y%29%2F20\"

\n" ); document.write( "We know the percentage of red in the final mixture is 25; so
\n" ); document.write( "\"%28460%2B3y%29%2F20+=+25\"
\n" ); document.write( "\"460%2B3y+=+500\"
\n" ); document.write( "\"3y+=+40\"
\n" ); document.write( "\"y+=+40%2F3\"

\n" ); document.write( "The percentage of red paint in R is 40/3, or 13 1/3.
\n" ); document.write( "
\n" );