document.write( "Question 1091873: Find 2 equation of a circle that touch the line y=-x+9, the positive y-axis, and positive x-axis \n" ); document.write( "
Algebra.Com's Answer #706395 by ikleyn(52794)\"\" \"About 
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\n" ); document.write( "Find 2 \"highlight%28cross%28equation%29%29\" equations of a circle that touch the line y=-x+9, the positive y-axis, and positive x-axis.
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document.write( "1.  Since the circle touches the positive y-axis and positive x-axis,  its center lies in the angle bisector of the angle\r\n" );
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document.write( "    In other words, the center lies in the straight line y = x.\r\n" );
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document.write( "2.  There are two such circles in the Quadrant I.\r\n" );
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document.write( "    The smaller circle lies inside the right angled triangle formed by the coordinate x- and y-axes and the straight line y = -x + 9. \r\n" );
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document.write( "    It is inscribed circle to this triangle.\r\n" );
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document.write( "    The other, the larger circle lies outside this triangle and makes external touching with its hypotenuse.\r\n" );
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document.write( "3.  Let us solve the problem for the larger circle first.\r\n" );
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document.write( "    From what I said above, it is clear that the point (4.5,4.5) lies in the circle and is the touching point.\r\n" );
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document.write( "    Now, if you make a sketch, you will easily get the equation for the radius R of the circle:\r\n" );
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document.write( "        \"R+%2B+4.5%2Asqrt%282%29\" = \"R%2Asqrt%282%29\",\r\n" );
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document.write( "    which implies\r\n" );
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document.write( "        \"R%2Asqrt%282%29-R\" = \"4.5%2Asqrt2%29\"  ====>  \"R\".\"%28sqrt%282%29-1%29\" = \"4.5%2Asqrt%282%29\"  ====>  R = \"%284.5%2Asqrt%282%29%29%2F%28sqrt%282%29-1%29\" =  = \"9%2B4.5%2Asqrt%282%29\".\r\n" );
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document.write( "    Thus the coordinates of the center are (x,y) = (R,R) and the radius is R = \"9%2B4.5%2Asqrt%282%29\" = 15.364    (approximately)    (1)\r\n" );
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document.write( "    The equation of the larger circle is  \"%28x-R%29%5E2\" + \"%28y-R%29%5E2\" = \"R%5E2\"  with  R  expressed in the formula (1).\r\n" );
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document.write( "4.  Let us solve the problem for the smaller circle now.\r\n" );
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document.write( "    If you make a sketch, you will easily get the equation for the radius r of the smaller circle:\r\n" );
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document.write( "        \"4.5%2Asqrt%282%29+-+r\" = \"r%2Asqrt%282%29\",\r\n" );
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document.write( "    which implies\r\n" );
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document.write( "        \"r%2Asqrt%282%29%2Br\" = \"4.5%2Asqrt2%29\"  ====>  \"r\".\"%28sqrt%282%29%2B1%29\" = \"4.5%2Asqrt%282%29\"  ====>  r = \"%284.5%2Asqrt%282%29%29%2F%28sqrt%282%29%2B1%29\" =  = \"9-4.5%2Asqrt%282%29\".\r\n" );
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document.write( "    Thus the coordinates of the center are (x,y) = (r,r) and the radius is r = \"9-4.5%2Asqrt%282%29\" = 2.636   (approximately)    (2)\r\n" );
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document.write( "    The equation of the smaller circle is  \"%28x-r%29%5E2\" + \"%28y-r%29%5E2\" = \"r%5E2\"  with  r  expressed by the formula (2).\r\n" );
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