document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1091815>Question 1091815</A>: <I><SPAN STYLE=\"word-break: break-all;\"> prove that,7log(10/9)+3log(81/80)=2log(25/24)+log2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #706327 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=706327\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One can show they are equivalent<BR>\n" );
document.write( "log (10/9)^7*(81/80)^3=log 10^7*9^6, substituting 9^2 for 81<BR>\n" );
document.write( "divided by 9^7*(8*10)^3<BR>\n" );
document.write( "That reduces to log 10^7/9*512*10^3, where *8^3=512<BR>\n" );
document.write( "This is 10^4/512*9=10,000/512*9, or 625/32*9 or log (625/288)<BR>\n" );
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document.write( "The right side is log (25^2/24^2)*2<BR>\n" );
document.write( "This is log (625/576)*2,, or log (625/288) </SPAN>\n" );
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