document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1091817>Question 1091817</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2)Sumalee's school is selling tickets to a spring musical. On the first day of ticket sales the school sold<BR>\n" );
document.write( "6 adult tickets and 1 student ticket for a total of $23. The school took in $106 on the second day by<BR>\n" );
document.write( "selling 12 adult tickets and 14 student tickets. Find the price of an adult ticket and the price of a<BR>\n" );
document.write( "student ticket.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #706325 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=706325\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6A+1S=23, where A is an adult ticket and S is a student ticket<BR>\n" );
document.write( "12A+14S=106<BR>\n" );
document.write( "from equation 1, S=23-6A<BR>\n" );
document.write( "substitute into equation 2.<BR>\n" );
document.write( "12A+14(23-6A)=106<BR>\n" );
document.write( "12A+312-84A=106<BR>\n" );
document.write( "-72A=-216<BR>\n" );
document.write( "A=$3<BR>\n" );
document.write( "use that in first equation and get 18+S=23, so S=$5.<BR>\n" );
document.write( "check in second equation and 36+70=106<BR>\n" );
document.write( "Adult ticket is $3 and student ticket is $5. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );