document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1091785>Question 1091785</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Katherine borrowed $4000 in two loans. One loan charged 7% interest, and the other charged 1.5% interest. After 1 year, Katherine paid $225 in interest. Find the amount borrowed in each loan account.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #706320 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=706320\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let n be the amount borrowed at 7%. Then the amount borrowed at 1.5% would be 4000-n. So:<BR>\n" );
document.write( "0.07n+0.015(4000-n)=225<BR>\n" );
document.write( "Solve for n<BR>\n" );
document.write( "&#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
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