document.write( "Question 1091799: Problem Solving
\n" ); document.write( "How many liters of a 20% solution should be added to a 450 L solution which contains 35% alcohol so that the resulting mixture will be 30% alcohol? With solution?
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Algebra.Com's Answer #706315 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+x+\"$ = liters of 20% solution needed
\n" ); document.write( " $\"+%28+.2x+%2B+.35%2A450+%29+%2F+%28+x+%2B+450+%29+=+.3+\"$
\n" ); document.write( " $\"+.2x+%2B+157.5+=+.3%2A%28+x+%2B+450+%29+\"$
\n" ); document.write( " $\"+.2x+%2B+157.5+=+.3x+%2B+135+\"$
\n" ); document.write( " $\"+.1x+=+22.5+\"$
\n" ); document.write( " $\"+x+=+225+\"$
\n" ); document.write( "225 liters of 20% solution must be added
\n" ); document.write( "----------------------------------------
\n" ); document.write( "check:
\n" ); document.write( " $\"+%28+.2%2A225+%2B+.35%2A450+%29+%2F+%28+225+%2B+450+%29+=+.3+\"$
\n" ); document.write( " $\"+%28+45+%2B+157.5+%29+%2F+675+=+.3+\"$
\n" ); document.write( " $\"+202.5+=+.3%2A675+\"$
\n" ); document.write( " $\"+202.5+=+202.5+\"$
\n" ); document.write( "OK \n" ); document.write( "

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