document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1091744>Question 1091744</A>: <I><SPAN STYLE=\"word-break: break-all;\"> She is 25 years old and plans to invest $4,600 every year in an IRA account, beginning at the end of this year until she turns 65 years old. If the IRA investment will earn 10.10 percent annually, how much will she have in 40 years, when she turns 65? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #706212 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=706212\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is <BR>\n" );
document.write( "Final=annual amount ((1+(r/n)^N)-1)/(r/n); r/n is just r, because one compounding per year.<BR>\n" );
document.write( "=4600(1+.1010)^40-1/(0.1010)<BR>\n" );
document.write( "round at end<BR>\n" );
document.write( "$2092069.11<BR>\n" );
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