document.write( "Question 1091694: Ama's age is two thirds that of her sister. four years ago Ama's age was half the sister. how old is the sister
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Algebra.Com's Answer #706203 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Ama's age is two thirds that of her sister.
\n" ); document.write( " four years ago Ama's age was half the sister.
\n" ); document.write( " how old is the sister
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\n" ); document.write( "let a = A's age
\n" ); document.write( "let s = sis's age
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\n" ); document.write( "Write an equation for each statement\r
\n" ); document.write( "\n" ); document.write( " Ama's age is two thirds that of her sister.
\n" ); document.write( "a = $\"2%2F3\"$ s
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\n" ); document.write( " four years ago Ama's age was half the sister.
\n" ); document.write( "a - 4 = $\"1%2F2\"$ (s-4)
\n" ); document.write( "Multiply both sides by 2
\n" ); document.write( "2(a-4) = s - 4
\n" ); document.write( "2a - 8 = s - 4
\n" ); document.write( "2a = s - 4 + 8
\n" ); document.write( "2a = s + 4
\n" ); document.write( "replace a with $\"2%2F3\"$ s
\n" ); document.write( "2( $\"2%2F3\"$ s) = s + 4
\n" ); document.write( " $\"4%2F3\"$ s = s + 4
\n" ); document.write( "multiply both sides by 3, get rid of the annoying fraction
\n" ); document.write( "4s = 3(s+4)
\n" ); document.write( "4s = 3s + 12
\n" ); document.write( "4s - 3s = 12
\n" ); document.write( " s = 12 yrs is the sister's age
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\n" ); document.write( "you should find a and then check the solutions in the 2nd statement\r
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