document.write( "Question 1091692: A mixture contains 24 quarts of water and acid solution, of which 60% is acid. How much of this solution should be drained and replaced with water for the solution to be 40% acid?
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Algebra.Com's Answer #706190 by ikleyn(52786)\"\" \"About 
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document.write( "Let V be the volume of the mixture to be drained and replaced with water.\r\n" );
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document.write( "Then the pure mixture contents in the final solution is  0.6*24 - 0.6*V quarts,\r\n" );
document.write( "while the total volume after replacement remains the same, 24 quarts.\r\n" );
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document.write( "So your concentration equation is \r\n" );
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document.write( "\"%280.6%2A24+-+0.6%2AV%29%2F24\" = 0.4.\r\n" );
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document.write( "To solve it, multiply both sides by 24:\r\n" );
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document.write( "0.6*24 - 0.6*V = 0.4*24,  ====>\r\n" );
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document.write( "0.6*V = 0.6*24 - 0.4*24 = 0.2*24  ====>  V = \"%280.2%2A24%29%2F0.6\" = \"%282%2A24%29%2F6\" = 2*4 = 8.\r\n" );
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document.write( "Answer.  8 quarts of the mixture must be drained and replaced.\r\n" );
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\n" ); document.write( "\n" ); document.write( "There is entire bunch of introductory lessons covering various types of mixture problems\r
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\n" ); document.write( "\n" ); document.write( "    - Word problems on mixtures for antifreeze solutions \r
\n" ); document.write( "\n" ); document.write( "    - Word problems on mixtures for alloys \r
\n" ); document.write( "\n" ); document.write( "    - Typical word problems on mixtures from the archive\r
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\n" ); document.write( "\n" ); document.write( "Read them and become an expert in solution mixture word problems.\r
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\n" ); document.write( "\n" ); document.write( "Also, you have this free of charge online textbook in ALGEBRA-I in this site\r
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\n" ); document.write( "\n" ); document.write( "The referred lessons are the part of this textbook in the section \"Word problems\" under the topic \"Mixture problems\".\r
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