document.write( "Question 1091733: For the transformation T, write the inverse T-1.\r
\n" ); document.write( "\n" ); document.write( "T: (x, y) --> ( 2x, y + 5)
\n" ); document.write( "T-1: (x, y)--> \r
\n" ); document.write( "\n" ); document.write( "A.) (x - 2, y - 5)
\n" ); document.write( "B.) (½x, y - 5)
\n" ); document.write( "C.) (2x - 1, y + 4)\r
\n" ); document.write( "\n" ); document.write( "Please explain. Thank you. \n" ); document.write( "
Algebra.Com's Answer #706189 by Edwin McCravy(20056)\"\" \"About 
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For the transformation T, write the inverse T-1.
\n" ); document.write( "T: (x, y) --> (2x, y + 5)
\n" ); document.write( "T-1 (x, y)-->
\n" ); document.write( "A.) (x - 2, y - 5)
\n" ); document.write( "B.) (½x, y - 5)
\n" ); document.write( "C.) (2x - 1, y + 4)
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document.write( "The inverse of T, written T-1, does the exact opposite to\r\n" );
document.write( "the coordinates as T does to them.\r\n" );
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document.write( "Transform T changes x to 2x, which is to double the first coordinate.\r\n" );
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document.write( "The opposite of doubling the first coordinate is halving the first \r\n" );
document.write( "coordinate, so T-1 takes x to ½x\r\n" );
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document.write( "Transform T also takes y to y+5, which is adding 5 to the second coordinate.\r\n" );
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document.write( "The opposite of adding 5 to the second coordinate is subtracting 5 from\r\n" );
document.write( "the second coordinate, so T-1 takes y to y-5.  \r\n" );
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document.write( "Therefore,\r\n" );
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document.write( "T-1: (x, y)--> (½x, y-5)\r\n" );
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document.write( "Correct answer is B.  \r\n" );
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document.write( "Edwin
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