document.write( "Question 1091256: you are given that the standing eye heights of women are normally distributed with a mean of 1524 mm and a standard deviation of 61mm\r
\n" ); document.write( "\n" ); document.write( "A. a door peephole is placed at a height that is uncomfortable for women with a standing eye height greater than 1615 mm, what percentage of women will find that height uncomfortable?\r
\n" ); document.write( "\n" ); document.write( "B. in selecting the height of a door peephole, the architect wants its height to be suitable for the highest 99% of standing eye heights of women. what standing eye height of women separates the highest 99% of standing eye heights from the lowest 1%?
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Algebra.Com's Answer #706178 by stanbon(75887)\"\" \"About 
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you are given that the standing eye heights of women are normally distributed with a mean of 1524 mm and a standard deviation of 61mm
\n" ); document.write( "A. a door peephole is placed at a height that is uncomfortable for women with a standing eye height greater than 1615 mm, what percentage of women will find that height uncomfortable?
\n" ); document.write( "z(1615) = (1615-1524)/61 = 1.4918
\n" ); document.write( "Ans: P(x > 1615) = P(z > 1.4918) = normalcdf(1.4918,100) = 0.0679
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\n" ); document.write( "B. in selecting the height of a door peephole, the architect wants its height to be suitable for the highest 99% of standing eye heights of women. what standing eye height of women separates the highest 99% of standing eye heights from the lowest 1%?
\n" ); document.write( "Find the z-value with a left-tail of 0.01
\n" ); document.write( "invNorm(0.01) = -2.3263
\n" ); document.write( "Find the corresponding height::
\n" ); document.write( "x = -2.3263*61+1524 = 1382.1 mm
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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