document.write( "Question 1091721: Find the value of a and b so that the graph of y=sqrt(ax + b) passes through points (-4,6) and (1,4). \n" ); document.write( "
Algebra.Com's Answer #706170 by MathLover1(20849)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " In triangle ABC, median AM is such that angle BAC is divided in ratio 1:2. AM is extended through M to D so that angle DBA is a right angle, then the ratio AC : AD is equal to \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a median is a line joining a vertex with the mid-point of the opposite side\r \n" ); document.write( "\n" ); document.write( "to find the value of \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "from eq.1 and eq.2 we have\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "now find \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so, your equation is: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |