document.write( "Question 14039: the first side of a triangle is 5 more than 3 times the third side. the second side is 5 less than twice the third side. if the perimeter is 60cm, how long is each side? \n" ); document.write( "
Algebra.Com's Answer #7061 by bam878s(77)\"\" \"About 
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Let x=length of third side, y=length of first side, and z=length of second side.
\n" ); document.write( "From the problem, we know
\n" ); document.write( "1. y=lenght of the first side= 5 more than 3 times the third side = 3x+5
\n" ); document.write( "2. z=length of the second side= 5 less than 2 times the third side = 2x-5
\n" ); document.write( "3. x=length of the third side.
\n" ); document.write( "4. The sum of these lengths, by definition is the perimeter.
\n" ); document.write( "We have,
\n" ); document.write( "perimeter=60= x + (3x+5) + (2x-5).
\n" ); document.write( "solve for x.
\n" ); document.write( "60=x+3x+5+2x-5
\n" ); document.write( "60=6x+5-5
\n" ); document.write( "60=6x
\n" ); document.write( "10=x\r
\n" ); document.write( "\n" ); document.write( "Now plug x back into your other equations to solve for the other sides.
\n" ); document.write( "y=length of first side=3x+5 = 3(10)+5 = 30+5 = 35
\n" ); document.write( "z=length of second side = 2x-5 = 2(10)-5= 20-5 = 15.\r
\n" ); document.write( "\n" ); document.write( "so
\n" ); document.write( "x=10
\n" ); document.write( "y=35
\n" ); document.write( "z=15. \n" ); document.write( "
\n" );