document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1091657>Question 1091657</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Kim is 2 years less than three times Beverly;s age. If the sum of their ages is 42, find their ages. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #706093 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=706093\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Word problems: read carefully, then translate the words into math terms:<BR>\n" );
document.write( "Kim is 2 years LESS (-2) than three TIMES Beverly (3 × B)<BR>\n" );
document.write( "Together: 3B-2 = K<BR>\n" );
document.write( "---------------------------------<BR>\n" );
document.write( "Next:<BR>\n" );
document.write( "K+B = 42 substitute for K:<BR>\n" );
document.write( "3B-2+B = 42<BR>\n" );
document.write( "3B+B = 44<BR>\n" );
document.write( "4B = 44<BR>\n" );
document.write( "B = 11<BR>\n" );
document.write( "And Kim:<BR>\n" );
document.write( "3B-2 = K<BR>\n" );
document.write( "3(11)-2 = K<BR>\n" );
document.write( "33-2 = 31 = K<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );