document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=96982>Question 96982</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The measures of an angle and its complement differ by 22 degrees. Find the measures of the angles. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #70608 by </B><A HREF=/tutors/aboutme.mpl?userid=mathslover><B>mathslover(157)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathslover><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mathslover><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=70608\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the measures of the angles be x and y\r<BR>\n" );
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document.write( "Since sum of complementary angles is 90 degrees\r<BR>\n" );
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document.write( "x + y = 90   .....(1)\r<BR>\n" );
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document.write( "also given \r<BR>\n" );
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document.write( "x - y = 22   ......(2)\r<BR>\n" );
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document.write( "Adding equations 1 and 2\r<BR>\n" );
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document.write( "we have 2x=112<BR>\n" );
document.write( "or x=56<BR>\n" );
document.write( "therefore y = 90 - 56 =34\r<BR>\n" );
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document.write( "angles are 56 and 34 </SPAN>\n" );
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