document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=96985>Question 96985</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a yard is 130 ft. IF the length is 10 less than 2 times the width, write an equation for the perimeter .... ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #70607 by </B><A HREF=/tutors/aboutme.mpl?userid=coyote><B>coyote(32)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=coyote><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=70607\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> p = 2w + 2l<BR>\n" );
document.write( "so the equation is<BR>\n" );
document.write( "130 = 2w + 2(2w - 10)\r<BR>\n" );
document.write( "\n" );
document.write( "To solve:<BR>\n" );
document.write( "130 = 2w + 4w - 20<BR>\n" );
document.write( "130 = 6w - 20<BR>\n" );
document.write( "150 = 6w<BR>\n" );
document.write( "25 = w </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );