document.write( "Question 1091632: Hi
\n" ); document.write( "a ship travels 45 km in a direction with a bearing of 132 degrees. How far south of its starting point
\n" ); document.write( "is the ship.\r
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Algebra.Com's Answer #706068 by Theo(13342)\"\" \"About 
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a bearing of 132 degrees is an angle that is clockwise from north.
\n" ); document.write( "that would be angle NAB in the picture.\r
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\n" ); document.write( "\n" ); document.write( "AB is the distance the ship travels along that direction.\r
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\n" ); document.write( "\n" ); document.write( "BC is the line formed by extending a horizontal line from B to the north south line of NC.\r
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\n" ); document.write( "\n" ); document.write( "48 degrees is angle CAB which is the supplement to angle NAB.\r
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\n" ); document.write( "\n" ); document.write( "the triangle formed is ABC.\r
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\n" ); document.write( "\n" ); document.write( "angle BAC is 48 degrees.
\n" ); document.write( "angle BCA is 90 degrees.
\n" ); document.write( "angle ABC is complement to BAC = 90 - 48 = 42 degrees.\r
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\n" ); document.write( "\n" ); document.write( "the line AC is how far south the ship is.
\n" ); document.write( "the line AB is the distance the ship traveled and also the hypotenuse of right triangle ACB.\r
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\n" ); document.write( "\n" ); document.write( "cos(48) = AC / AB.
\n" ); document.write( "AC = AB * cos(BAC) = 45 * cos(48) = 30.11 rounded to 2 decimal place.\r
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\n" ); document.write( "\n" ); document.write( "sin((ABC) = AC / AB.
\n" ); document.write( "AC = AB * sin(ABC) = 45 * sin(42) = 30.11 rounded to 2 decimal places.\r
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\n" ); document.write( "\n" ); document.write( "either way you get AC= 30.11 kilometers.\r
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